8x^2-22x-30=0

Solution for 8x^2-22x-30=0 equation:

8x^2-22x-30=0

a = 8; b = -22; c = -30;
Δ = b2-4ac
Δ = -222-4·8·(-30)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-38}{2*8}=\frac{-16}{16}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+38}{2*8}=\frac{60}{16}
=3+3/4
$